check if breckets clossing properly check if breckets clossing properly

The solution for “check if breckets clossing properly check if breckets clossing properly” can be found here. The following code will assist you in solving the problem.

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def valid_paren(input_str):

  # Declaraing a stack.

  stack = []

  # Iterating over the entire string

  for paren in input_str:

    # If the input string contains an opening parenthesis,

    # push in on to the stack.

    if paren == ‘(‘ or paren == ‘[‘ or paren == ‘{‘:

      stack.append(paren)

    else:

      # In the case of valid parentheses, the stack cannot be

      # be empty if a closing parenthesis is encountered.

      if not stack:

        print(input_str, “contains invalid parentheses.”)

        return

      else:

        # If the input string contains a closing bracket,

        # then pop the corresponding opening parenthesis if

        # present.

        top = stack[-1]

        if paren == ‘)’ and top == ‘(‘ or \

        paren == ‘]’ and top == ‘[‘ or \

        paren == ‘}’ and top == ‘{‘:

          stack.pop()

  # Checking the status of the stack to determine the

  # validity of the string.

  if not stack:

    print(input_str, “contains valid parentheses.”)

  else:

    print(input_str, “contains invalid parentheses.”)
input1 = “{{}}()[()]”

input2 = “{][}”

input3 = “)”

valid_paren(input1)

valid_paren(input2)

valid_paren(input3)

input4 = “([)]”

valid_paren(input4)

input5 = ‘() [{}]’

valid_paren(input5)def valid_paren(input_str):

  # Declaraing a stack.

  stack = []

  # Iterating over the entire string

  for paren in input_str:

    # If the input string contains an opening parenthesis,

    # push in on to the stack.

    if paren == ‘(‘ or paren == ‘[‘ or paren == ‘{‘:

      stack.append(paren)

    else:

      # In the case of valid parentheses, the stack cannot be

      # be empty if a closing parenthesis is encountered.

      if not stack:

        print(input_str, “contains invalid parentheses.”)

        return

      else:

        # If the input string contains a closing bracket,

        # then pop the corresponding opening parenthesis if

        # present.

        top = stack[-1]

        if paren == ‘)’ and top == ‘(‘ or \

        paren == ‘]’ and top == ‘[‘ or \

        paren == ‘}’ and top == ‘{‘:

          stack.pop()

  # Checking the status of the stack to determine the

  # validity of the string.

  if not stack:

    print(input_str, “contains valid parentheses.”)

  else:

    print(input_str, “contains invalid parentheses.”)
input1 = “{{}}()[()]”

input2 = “{][}”

input3 = “)”

valid_paren(input1)

valid_paren(input2)

valid_paren(input3)

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