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The solution for “spade operator typescript spade operator typescript spade operator typescript” can be found here. The following code will assist you in solving the problem.

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let origObjectOne = {a: 1, b: 2, c: 3};                 //{a: 1, b: 2, c: 3}

let origObjectTwo = {d: 4, e: 5, f: 6};                 //{d: 4, e: 5, f: 6}

 

//Create new object from existing object

let copyObject = {…origObjectOne};                        //{a: 1, b: 2, c: 3}

 

//Create new object from existing object + more elements

let newObject = {…origObjectOne, g: 7, h: 8};             //{a: 1, b: 2, c: 3, g: 7, h: 8}

 

//Create object by merging two objects

let mergedObject = {…origObjectOne, …origObjectTwo};    //{a: 1, b: 2, c: 3, d: 4, e: 5, f: 6}

let origArrayOne = [ 1, 2, 3];                          //1,2,3

let origArrayTwo = [ 4, 5, 6];                          //4,5,6

 

//Create new array from existing array

let copyArray = […origArrayOne];                      //1,2,3

 

//Create new array from existing array + more elements

let newArray = […origArrayOne, 7, 8];             //1,2,3,7,8

 

//Create array by merging two arrays

let mergedArray = […origArrayOne, …origArrayTwo];   //1,2,3,4,5,6

function myFunction(x, y, z) {

    console.log( x );

    console.log( y );

    console.log( z );

}

 

var parametersArray = [0, 1, 2];

 

myFunction(…parametersArray);     //0, 1, 2

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