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The solution for “spade operator typescript spade operator typescript spade operator typescript” can be found here. The following code will assist you in solving the problem.

let origObjectOne = {a: 1, b: 2, c: 3};                 //{a: 1, b: 2, c: 3}
let origObjectTwo = {d: 4, e: 5, f: 6};                 //{d: 4, e: 5, f: 6}
 
//Create new object from existing object
let copyObject = {…origObjectOne};                        //{a: 1, b: 2, c: 3}
 
//Create new object from existing object + more elements
let newObject = {…origObjectOne, g: 7, h: 8};             //{a: 1, b: 2, c: 3, g: 7, h: 8}
 
//Create object by merging two objects
let mergedObject = {…origObjectOne, …origObjectTwo};    //{a: 1, b: 2, c: 3, d: 4, e: 5, f: 6}
let origArrayOne = [ 1, 2, 3];                          //1,2,3
let origArrayTwo = [ 4, 5, 6];                          //4,5,6
 
//Create new array from existing array
let copyArray = […origArrayOne];                      //1,2,3
 
//Create new array from existing array + more elements
let newArray = […origArrayOne, 7, 8];             //1,2,3,7,8
 
//Create array by merging two arrays
let mergedArray = […origArrayOne, …origArrayTwo];   //1,2,3,4,5,6
function myFunction(x, y, z) {
    console.log( x );
    console.log( y );
    console.log( z );
}
 
var parametersArray = [0, 1, 2];
 
myFunction(…parametersArray);     //0, 1, 2

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